TS EAMCET · Physics · Current Electricity
Each of the six ideal batteries of emf \(20 \mathrm{~V}\) is comnected to an external resistance of \(4 \Omega\) as shown in the figure. The current through the resistance is
- A \(6 \mathrm{~A}\)
- B \(3 \mathrm{~A}\)
- C \(4 \mathrm{~A}\)
- D \(15 \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(15 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Resistance \(=4 \Omega\) The equivalent emf of the combination \[ E_{e q}=n E=3 \times 20=60 \] The cell have no internal resistance. \(\therefore\) Main current flowing through the load \[ i=\frac{n E}{R}=\frac{60}{4}=15 \mathrm{~A} \]
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