TS EAMCET · Physics · Motion In One Dimension
A particle starts from origin at time \(t=0\) and moves in positive \(x\)-direction. Its velocity \(\mathbf{v}\) varies with times as \(\mathbf{v}=10 \hat{t} \mathrm{~cm} / \mathrm{s}\). The distance covered by the particle in \(8 \mathrm{~s}\) will be
- A \(320 \mathrm{~cm}\)
- B \(80 \mathrm{~cm}\)
- C \(120 \mathrm{~cm}\)
- D \(640 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(A) \(320 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Given that, \(t=0, \mathbf{v}=10 \hat{i} \mathrm{~cm} / \mathrm{s}\) So, acceleration, \(a=\frac{d v}{d t}=10 \hat{\mathbf{i}} \mathrm{cm} / \mathrm{s}\) According to second equation of motion,…
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