TS EAMCET · Physics · Electromagnetic Induction
A varying current in a coil changes from \(10 \mathrm{~A}\) to zero in \(1.5 \mathrm{~s}\). If the average emf induced in the coil is \(200 \mathrm{~V}\), the self-inductance of the coil is
- A \(25 \mathrm{H}\)
- B \(30 \mathrm{H}\)
- C \(50 \mathrm{H}\)
- D \(45 \mathrm{H}\)
Answer & Solution
Correct Answer
(B) \(30 \mathrm{H}\)
Step-by-step Solution
Detailed explanation
Self-induced emf in coil is given by \(E=L\left(\frac{d I}{d t}\right)\) Here, \(E=200 \mathrm{~V}, \frac{d I}{d t}=\left(\frac{10-0}{1.5}\right) \mathrm{A} / \mathrm{s}\) So, self-inductance of coil, \(L=\frac{E}{d I / d t}=\frac{200}{\left(\frac{10-0}{1.5}\right)}\)…
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