TS EAMCET · Physics · Ray Optics
A convex lens has its radii of curvature equal. The focal length of the lens is \(f\). If it is divided vertically into two identical plano-convex lenses by cutting it, then the focal length of the plano-convex lens is ( \(\mu=\) the refractive index of the material of the lens)
- A \(f\)
- B \(\frac{f}{2}\)
- C \(2 f\)
- D \((\mu-1) f\)
Answer & Solution
Correct Answer
(C) \(2 f\)
Step-by-step Solution
Detailed explanation
The given, \(R_1=R, R_2=-R\) \( f=F \) Lens Maker's formula \( \begin{aligned} \frac{1}{F} & =(\mu-1)\left[\frac{1}{R_1}-\frac{1}{R_2}\right] \\ \frac{1}{f} & =(\mu-1)\left[\frac{1}{R}+\frac{1}{R}\right] \\ f & =\frac{R}{2(\mu-1)} \\ R & =2 f(\mu-1) \end{aligned} \) Now, it is…
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