TS EAMCET · Physics · Mechanical Properties of Solids
Two blocks of masses \(1 \mathrm{~kg}\) and \(2 \mathrm{~kg}\) are connected by a metal wire going over a smooth pulley. The breaking stress of metal is \(\frac{40}{3 \pi} \times 10^6 \mathrm{Nm}^{-2}\). What should be the minimum radius of wire used if it should not break? \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
- A 0.5 mm
- B 1 mm
- C 1.5 mm
- D 2 mm
Answer & Solution
Correct Answer
(C) 1.5 mm
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Breaking stress }=\frac{F}{A} \\ & \text { Here, breaking stress }=\frac{40}{3 \pi} \times 10^6 \mathrm{Nm}^{-2} \\ & \Rightarrow \quad \frac{40}{3 \pi} \times 10^6=\frac{3 \times 10}{\pi r^2} \\ & \Rightarrow \quad r^2=\frac{9}{4} \times…
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