TS EAMCET · Physics · Ray Optics
A convex lens and a concave lens, each with focal length of \(4 \mathrm{~cm}\) are separated by a distance of \(6 \mathrm{~cm}\) along their axis. An object is placed \(8 \mathrm{~cm}\) before the convex lens. The distance between the object and its image is
- A \(10 \mathrm{~cm}\)
- B \(15 \mathrm{~cm}\)
- C \(18 \mathrm{~cm}\)
- D \(24 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(C) \(18 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
The given situation is shown below For convex lens, \(u=-8 \mathrm{~cm}, f=4 \mathrm{~cm}\) \(\frac{1}{v}-\frac{1}{u}=\frac{1}{f} \Rightarrow \frac{1}{v}=\frac{1}{4}+\frac{1}{-8} \Rightarrow \frac{1}{v}=\frac{1}{8} \Rightarrow v=8 \mathrm{~cm}\) For concave lens, image of convex…
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