TS EAMCET · Physics · Laws of Motion
Imagine a person standing on a weighing machine placed inside an elevator. The elevator first accelerates, then moves with a constant velocity and finally decelerates to stop. The maximum and minimum weight recorded are \(80 \mathrm{~kg}\) and \(64 \mathrm{~kg}\), respectively. Find out the true weight of that person considering \(\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)\).
- A 70 kg
- B 85 kg
- C 72 kg
- D 65 kg
Answer & Solution
Correct Answer
(C) 72 kg
Step-by-step Solution
Detailed explanation
When the lift accelerates with acceleration \(a\), then the normal reaction force \(N\) by the elevator on the person is given as \(\therefore N-m g=m a\) (where, \(m\) is the actual mass of that person) When the lift deaccelerates with acceleration \(a\) then, \(m g-N=m a\)…
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