TS EAMCET · Physics · Center of Mass Momentum and Collision
A bullet of mass \(0.02 \mathrm{~kg}\) travelling horizontally with velocity \(250 \mathrm{~ms}^{-1}\) strikes a block of wood of mass \(0.23 \mathrm{~kg}\) which rests on a rough horizontal surface. After the impact, the block and bullet move together and come to rest after travelling a distance of \(40 \mathrm{~m}\). The coefficient of sliding friction of the rough surface is \(\left(g=9.8 \mathrm{~ms}^{-2}\right)\)
- A 0.75
- B 0.61
- C 0.51
- D 0.3
Answer & Solution
Correct Answer
(C) 0.51
Step-by-step Solution
Detailed explanation
After impact the bullet and block move together and comes to rest after covering a distance of \(40 \mathrm{~m}\). By conservation of momentum \(\begin{gathered} m_1 u_1+m_2 u_2=m_1 v_1+m_2 v_2 \\ \text { or } \quad 0.02 \times 250+0.23 \times 0=0.02 v+0.23 v \end{gathered}\)…
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