TS EAMCET · Physics · Thermal Properties of Matter
A meter scale made of steel, reads accurately at \(25^{\circ} \mathrm{C}\). Suppose in an experiment an accuracy of \(0.06 \mathrm{~mm}\) in \(1 \mathrm{~m}\) is required, the range of temperature in which the experiment can be performed with this meter scale is (Coefficient of linear expansion of steel is \(11 \times 10^{-6} /{ }^{\circ} \mathrm{C}\) )
- A \(19^{\circ} \mathrm{C}\) to \(31^{\circ} \mathrm{C}\)
- B \(25^{\circ} \mathrm{C}\) to \(32^{\circ} \mathrm{C}\)
- C \(18^{\circ} \mathrm{C}\) to \(25^{\circ} \mathrm{C}\)
- D \(18^{\circ} \mathrm{C}\) to \(32^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(19^{\circ} \mathrm{C}\) to \(31^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given, Coefficient of linear expansion of steel, \[ \alpha=11 \times 10^{-6} /{ }^{\circ} \mathrm{C} \] We know that, \[ \Delta l=l \alpha \Delta t \Rightarrow \Delta t=\frac{\Delta l}{l \alpha} \] Here, \(\Delta l=6 \times 10^{-5} \mathrm{~m} \Rightarrow l=1 \mathrm{~m}\)…
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