TS EAMCET · Physics · Motion In Two Dimensions
A body projected at certain angle \(\left(\neq 90^{\circ}\right)\) from the ground crosses a point in its path at a time of 2.3 s and from there it reaches the ground after a time of 5.7 s. The maximum height reached by the body is
\(\left(\right.\) Acceleration due to gravity \(\left.=10 \mathrm{~ms}^{-2}\right)\)
- A 80 m
- B 120 m
- C 40 m
- D 160 m
Answer & Solution
Correct Answer
(A) 80 m
Step-by-step Solution
Detailed explanation
\(T = t_1 + t_2 = 2.3 \text{ s} + 5.7 \text{ s} = 8.0 \text{ s}\) \(t_h = T/2 = 8.0 \text{ s} / 2 = 4.0 \text{ s}\) \(H = \frac{1}{2} g t_h^2 = \frac{1}{2} (10 \text{ ms}^{-2}) (4.0 \text{ s})^2\) \(H = 5 \text{ ms}^{-2} \times 16 \text{ s}^2 = 80 \text{ m}\)
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