TS EAMCET · Physics · Gravitation
A body of mass \(m\) rises to height \(h=R / 5\) from the earth's surface, where \(R\) is earth's radius. If \(g\) is acceleration due to gravity at earth's surface, the increase in potential energy is
- A \(\mathrm{mg} / \mathrm{h}\)
- B \(\frac{5}{6} \mathrm{mgh}\)
- C \(\quad \frac{3}{5} \mathrm{mgh}\)
- D \(\frac{6}{7} \mathrm{mgh}\)
Answer & Solution
Correct Answer
(B) \(\frac{5}{6} \mathrm{mgh}\)
Step-by-step Solution
Detailed explanation
Given \(\mathrm{h}=\frac{\mathrm{R}}{5}\) Potential Energy at surface of the earth, \(\left(\mathrm{PE}_1\right)=-\frac{\mathrm{GMm}}{\mathrm{R}}\) Potential Energy at height \(h=\frac{R}{5},\left(P_2\right)=-\frac{G M m}{R+\frac{R}{5}}=-\frac{5 G M m}{6 R}\) Increase in…
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