TS EAMCET · Physics · Motion In One Dimension
A motor-bike starts from rest, attains a velocity of \(10 \mathrm{~m} / \mathrm{s}\) with an acceleration of \(0.5 \mathrm{~m} / \mathrm{s}^2\), travels \(10 \mathrm{~km}\) with this uniform velocity and then comes to halt with a uniform deceleration of \(0.2 \mathrm{~m} / \mathrm{s}^2\). The total time of travel is
- A 1070 s
- B 1050 s
- C 1150 s
- D 1170 s
Answer & Solution
Correct Answer
(A) 1070 s
Step-by-step Solution
Detailed explanation
The given situation of entire motion of motor bike is shown in the figure. If time taken by the motorbike to reach from point \(A\) to \(B\) is \(t_{A B}\), then for \(A\) to \(B\), \(v_A=0, v_B=10 \mathrm{~ms}^{-1}, a=0.5 \mathrm{~ms}^{-2}\) \(\therefore\) From equation,…
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