TS EAMCET · Physics · Oscillations
A body of mass \(0.3 \mathrm{~kg}\) hangs by a spring with a force constant of \(50 \mathrm{~N} / \mathrm{m}\). The amplitude of oscillations is damped and reaches \(\frac{1}{e}\) of its original value in about 100 oscillations. If \(\omega\) and \(\omega^{\prime}\) are the angular frequencies of undamped and damped oscillations respectively, then percentage of \(\left(\frac{\omega-\omega}{\omega}\right)\) is
- A \(\left(\frac{1}{800 \pi}\right)\)
- B \(\left(\frac{\pi^2}{600}\right)\)
- C \(\left(\frac{1}{800 \pi^2}\right)\)
- D \(\left(\frac{\pi}{400}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{1}{800 \pi^2}\right)\)
Step-by-step Solution
Detailed explanation
Hint The displacement of a spring mass oscillator, \(X=A e^{-b t / 2 m} \cos \left(\omega^{\prime} t+\phi\right)\) where, \(\omega^{\prime}=\) angular frequency of damped oscillation and \(\omega^{\prime}=\omega_0 \sqrt{1-\frac{b^2}{4 m^2 \omega_0^2}}\)
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