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TS EAMCET · Physics · Electromagnetic Waves

On a particular day, the sun delivers an average power of \(\left(\frac{6}{\pi} \times 10^3\right) \frac{\mathrm{W}}{\mathrm{m}^2}\) to the top of Earth's atmosphere. Find the amplitude of magnetic field for the electromagnetic waves above atmosphere. (Take \(\mu_0=4 \pi \times 10^{-7}\) SI unit)

  1. A \(5 \times 10^{-5} \mathrm{~T}\)
  2. B \(4 \times 10^{-6} \mathrm{~T}\)
  3. C \(6 \times 10^{-6} \mathrm{~T}\)
  4. D \(3 \times 10^{-5} \mathrm{~T}\)
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Answer & Solution

Correct Answer

(B) \(4 \times 10^{-6} \mathrm{~T}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \mathrm{I}=\frac{\mathrm{B}_0^2 \mathrm{C}}{2 \mu_0} \\ & \Rightarrow \quad \mathrm{B}_0^2=\frac{2 \mu_0 \mathrm{I}}{\mathrm{C}} \\ & \Rightarrow \quad \mathrm{B}_0^2=\frac{2 \times 4 \pi \times 10^{-7} \times \frac{6}{\pi} \times 10^3}{3 \times 10^8} \\ &…

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