TS EAMCET · Physics · Electromagnetic Waves
On a particular day, the sun delivers an average power of \(\left(\frac{6}{\pi} \times 10^3\right) \frac{\mathrm{W}}{\mathrm{m}^2}\) to the top of Earth's atmosphere. Find the amplitude of magnetic field for the electromagnetic waves above atmosphere. (Take \(\mu_0=4 \pi \times 10^{-7}\) SI unit)
- A \(5 \times 10^{-5} \mathrm{~T}\)
- B \(4 \times 10^{-6} \mathrm{~T}\)
- C \(6 \times 10^{-6} \mathrm{~T}\)
- D \(3 \times 10^{-5} \mathrm{~T}\)
Answer & Solution
Correct Answer
(B) \(4 \times 10^{-6} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{I}=\frac{\mathrm{B}_0^2 \mathrm{C}}{2 \mu_0} \\ & \Rightarrow \quad \mathrm{B}_0^2=\frac{2 \mu_0 \mathrm{I}}{\mathrm{C}} \\ & \Rightarrow \quad \mathrm{B}_0^2=\frac{2 \times 4 \pi \times 10^{-7} \times \frac{6}{\pi} \times 10^3}{3 \times 10^8} \\ &…
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