TS EAMCET · Physics · Work Power Energy
A ball of mass \(2 \mathrm{~kg}\) is moving in \(x y\)-plane with a potential energy given as \(U=(12 x+16 y) \mathrm{J}, x\) and \(y\) being in metre. Assume the initial position of the ball at \(t=0\) is at origin \((0,0)\) and it is moving with a velocity of \((15 \hat{\mathbf{i}}+20 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}\). Then, identify the correct statement.
- A The path of the ball is parabolic.
- B The direction of motion of the ball initially at \(t=0\) is parallel to the direction of acceleration.
- C The speed of the ball at \(t=2 \mathrm{~s}\) is \(5 \mathrm{~m} / \mathrm{s}\).
- D The magnitude of acceleration of the ball is \(8 \mathrm{~m} / \mathrm{s}^2\).
Answer & Solution
Correct Answer
(C) The speed of the ball at \(t=2 \mathrm{~s}\) is \(5 \mathrm{~m} / \mathrm{s}\).
Step-by-step Solution
Detailed explanation
Mass of the ball, \(m=2 \mathrm{~kg}\) Patential energy, \(U=(12 x+16 y) \mathrm{J}\) \(\therefore\) Force applied on it, \(\mathbf{F}=-\frac{d U}{d x} \hat{\mathbf{i}}-\frac{d U}{d y} \hat{\mathbf{j}}\) \[ \Rightarrow \quad \mathbf{F}=-12 \hat{\mathbf{i}}-16 \hat{\mathbf{j}} \]…
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