TS EAMCET · Physics · Thermodynamics
3 moles of an ideal monoatomic gas performs \(A B C D A\) cyclic process as shown in figure below. The gas temperatures are \(T_A=400 \mathrm{~K}\), \(T_B=800 \mathrm{~K}, T_C=2400 \mathrm{~K}\) and \(T_D=1200 \mathrm{~K}\). The work done by the gas is (approximately) \((R=8.314 \mathrm{~J} / \mathrm{mol} \mathrm{K})\)
- A \(10 \mathrm{~kJ}\)
- B \(20 \mathrm{~kJ}\)
- C \(40 \mathrm{~kJ}\)
- D \(100 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(B) \(20 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
Processes \(A\) to \(B\) and \(C\) to \(D\) are parts of straight line graphs of form \(y=m x\). Also, \(p=\frac{\mu R}{V} T(\mu=3)\) \(p \propto T\) So, volume remains constant for the graphs \(A B\) and \(C D\). So, no work is done during processes for \(A\) to \(B\) and \(C\)…
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