TS EAMCET · Physics · Mechanical Properties of Solids
The Poisson's ratio of a material is 0.4 . If a force is applied to a wire of this material, there is a decrease of cross-sectional area by \(2 \%\). The percentage increase in its length is
- A \(3 \%\)
- B \(2.5 \%\)
- C \(1 \%\)
- D \(0.5 \%\)
Answer & Solution
Correct Answer
(B) \(2.5 \%\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Poission's ratio } \sigma=\frac{\Delta R / R}{\Delta l / l} \\ & \frac{\Delta l}{l}=\frac{\Delta R}{R} \times \frac{1}{\sigma} \\ & =\frac{\Delta R}{R} \times \frac{1}{0.4} \\ & \therefore \text { Increase in length }=\left(\frac{\Delta R}{R} \times…
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