TS EAMCET · Physics · Work Power Energy
A force of \(4 \mathrm{~N}\) acts on a \(10 \mathrm{~kg}\) body initially at rest. Let \(W_1\) is work done by force during \(0 \leq t \leq\) ls. Likewise \(W_2\) is the work done by force during ls \(\leq t \leq 2 \mathrm{~s}\), where \(t\) is time in second. The ratio \(\frac{W_2}{W_1}\) is
- A 1
- B 2
- C \(\frac{1}{2}\)
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
Mass of body, \(m=10 \mathrm{~kg}\) Force, \(\quad F=4 \mathrm{~N}\) Acceleration produced in the body due to applied force, \(a=\frac{F}{m}=\frac{4}{10}=0.4 \mathrm{~ms}^{-2}\) For \(0 \leq t \leq 1 \mathrm{~s}, t_1=1 \mathrm{~s}\) \(\therefore\) Distance travelled by the body…
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