TS EAMCET · Physics · Semiconductors
\(10^{10}\) electrons enter the emitter of a junction transistor in a time of \(0.4 \mu \mathrm{~s}\). If \(5 \%\) of the electrons are lost in the base, then the collector current is
- A 3.0 mA
- B 3.2 mA
- C 3.6 mA
- D 3.8 mA
Answer & Solution
Correct Answer
(D) 3.8 mA
Step-by-step Solution
Detailed explanation
\(Q_E = n_e \times e = 10^{10} \times 1.6 \times 10^{-19} \, \mathrm{C} = 1.6 \times 10^{-9} \, \mathrm{C}\) \(I_E = \frac{Q_E}{t} = \frac{1.6 \times 10^{-9} \, \mathrm{C}}{0.4 \times 10^{-6} \, \mathrm{s}} = 4 \times 10^{-3} \, \mathrm{A} = 4 \, \mathrm{mA}\)…
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