TS EAMCET · Physics · Motion In Two Dimensions
A stone projected from the ground with a velocity \(50 \mathrm{~ms}^{-1}\) at an angle of \(30^{\circ}\) with the horizontal crosses a wall after a time of \(3 \mathrm{~s}\). Then the horizontal distance beyond the wall that the stone strikes the ground is \(\left(\right.\) acceleration due to gravity \(\left.=10 \mathrm{~ms}^{-2}\right)\)
- A \(90.2 \mathrm{~m}\)
- B \(89.6 \mathrm{~m}\)
- C \(86.6 \mathrm{~m}\)
- D \(70.2 \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(86.6 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Velocity of stone, \(u=50 \mathrm{~m} / \mathrm{s}\) Range, \(\mathrm{R}=\frac{\mathrm{u}^2 \sin 2 \theta}{\mathrm{g}}\) \[ \begin{aligned} & =\frac{50^2 \sin 60}{10} \\ & =\frac{2500 \times \sqrt{3}}{2 \times 10} \\ & =216.5 \mathrm{~m} \end{aligned} \] Time of flight,…
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