TS EAMCET · Maths · Probability
The probability distribution of a random variable X is given below \begin{array}{c|c|c|c|c|c|c|c|c} \hlineX=x & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 \ \hlineP(X=x) & 0 & k & 2 k & 2 k & 3 k & k^2 & 2 k^2 & 7 k^2+k \ \hline \end{array} Then, \(P(0 < x < 4)\) is equal to
- A \(\frac{4}{5}\)
- B \(\frac{3}{5}\)
- C \(\frac{1}{2}\)
- D \(\frac{1}{4}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} P(0 < x < 4) & =P(x=1)+P(x=2)+P(x=3) \\ & =k+2 k+2 k=5 k \end{aligned}\) As we know that, sum of all probability events \(=1\)…
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