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TS EAMCET · Maths · Inverse Trigonometric Functions

If \(x>0, y>0, z>0, x y+y z+z x < 1\) and if \(\tan ^{-1} x+\tan ^{-1} y+\tan ^{-1} z=\pi\), then \(x+y+z\) equals to

  1. A \(0\)
  2. B \(x y z\)
  3. C \(3 x y z\)
  4. D \(\sqrt{x y z}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x y z\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { Given, } \tan ^{-1} x+\tan ^{-1} y+\tan ^{-1} z=\pi \\ & \Rightarrow \quad \tan ^{-1}\left(\frac{x+y+z-x y z}{1-x y-y z-z x}\right)=\pi \\ & \Rightarrow \quad \frac{x+y+z-x y z}{1-x y-y z-z x}=\tan \pi=0 \\ & \Rightarrow \quad x+y+z=x y z\end{aligned}

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