TS EAMCET · Maths · Indefinite Integration
\(\int \frac{2 x^3-4 x^2-x-3}{x^2-2 x-3} d x=\)
- A \(\frac{7}{2} \log |x-1|+\frac{3}{2} \log |x+3|+c\)
- B \(2 \log |x-1|+\frac{7}{2} \log |x+3|+c\)
- C \(2 x+\frac{1}{2} \log |x+1|+\frac{3}{4} \log |x-3|+c\)
- D \(x^2+2 \log |x+1|+3 \log |x-3|+c\)
Answer & Solution
Correct Answer
(D) \(x^2+2 \log |x+1|+3 \log |x-3|+c\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} & I=\int \frac{2 x^3-4 x^2-x-3}{x^2-2 x-3} d x \\ & I=\int\left(2 x+\frac{5 x-3}{(x+1)(x-3)}\right) d x \\ & I=\int\left(2 x+\frac{2}{x+1}+\frac{3}{x-3}\right) d x \\ & I=x^2+2 \log |x+1|+3 \log |x-3|+c \end{aligned} \]
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