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TS EAMCET · Maths · Circle

The vertex of the parabola (y-1)2=8(x-1) is at the centre of a circle and the parabola cuts that circle at the ends of its latus rectum. Then the equation of that circle is

  1. A x2+y2-2x-2y-18=0
  2. B x2+y2-2x-2y+18=0
  3. C x2+y2+2x+9y-16=0
  4. D x2+y2-2x-2y+16=0
Verified Solution

Answer & Solution

Correct Answer

(A) x2+y2-2x-2y-18=0

Step-by-step Solution

Detailed explanation

(y-1)2=8(x-1) Vertex→(1,1) Circle (x-1)2+(y-1)2=α2 Extremities of Lotus rectum →(3,5) It satisfies circle 22+42=α2 ⇒α2=20 x2+y2-2x-2y-18=0