TS EAMCET · Maths · Differential Equations
The general solution of the differential equation \(\frac{d y}{d x}=\) \(\sin (x-y)+\cos (x-y)\) is
- A \(\log \left|\frac{\tan \frac{(x-y)}{2}+1}{\tan \frac{(x-y)}{2}}\right|=x+c\)
- B \(\log \left|\frac{\tan \frac{(x-y)}{2}-1}{\tan \frac{(x-y)}{2}}\right|=x+c\)
- C \(\log \left|\frac{\tan (x-y)-1}{\tan (x-y)}\right|=x+c\)
- D \(\log \left|\frac{\sin (x-y)+\cos (x-y)}{\cos (x-y)}\right|=x+c\)
Answer & Solution
Correct Answer
(B) \(\log \left|\frac{\tan \frac{(x-y)}{2}-1}{\tan \frac{(x-y)}{2}}\right|=x+c\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}=\sin (x-y)+\cos (x-y)\) Put \(x-y=v\)…
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