TS EAMCET · Maths · Three Dimensional Geometry
The position vectors of the points \(A\) and \(B\) are respectively \(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}\) and \(2 \hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}\). If the points \(P\) and \(Q\) are respectively the orthogonal projections of \(A\) and \(B\) on the plane \(x+y+z=3\), then \(P Q=\)
- A \(\frac{2 \sqrt{2}}{\sqrt{3}}\)
- B \(\frac{\sqrt{3}}{2}\)
- C \(\frac{\sqrt{5}}{7}\)
- D \(\frac{\sqrt{7}}{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{2 \sqrt{2}}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
Given projections of \(A\) and \(B\) are \(P\) and \(Q\) respectively \(A(1,2,0) \text { and } B(2,1,1)\) Plane \(P: x+y+z=3\) Vector \(\perp^r\) to plane \(P\) : is \(\mathbf{n}=\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}\) \(\therefore\) vector equation of line \(A P\)…
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