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TS EAMCET · Maths · Straight Lines

If a straight line is passing through the point of intersection of the lines \(3 x-4 y+1=0\), \(5 x+y-1=0\) and making equal non-zero intercepts on the coordinate axes, then the area (in sq. units) of the triangle formed by this line with the coordinate axes, is

  1. A \(\frac{121}{1058}\)
  2. B \(\frac{121}{529}\)
  3. C \(\frac{529}{121}\)
  4. D \(\frac{1058}{121}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{121}{1058}\)

Step-by-step Solution

Detailed explanation

Equation of line passing through the point of intersection of lines \(3 x-4 y+1=0\) and \(5 x+y-1=0\) is \[ \begin{aligned} & (3 x-4 y+1)+\lambda(5 x+y-1)=0 \\ & \Rightarrow(3+5 \lambda) x+(-4+\lambda) y+1-\lambda=0 \end{aligned} \] Given line has equal intercepts…