TS EAMCET · Maths · Straight Lines
If a straight line is passing through the point of intersection of the lines \(3 x-4 y+1=0\), \(5 x+y-1=0\) and making equal non-zero intercepts on the coordinate axes, then the area (in sq. units) of the triangle formed by this line with the coordinate axes, is
- A \(\frac{121}{1058}\)
- B \(\frac{121}{529}\)
- C \(\frac{529}{121}\)
- D \(\frac{1058}{121}\)
Answer & Solution
Correct Answer
(A) \(\frac{121}{1058}\)
Step-by-step Solution
Detailed explanation
Equation of line passing through the point of intersection of lines \(3 x-4 y+1=0\) and \(5 x+y-1=0\) is \[ \begin{aligned} & (3 x-4 y+1)+\lambda(5 x+y-1)=0 \\ & \Rightarrow(3+5 \lambda) x+(-4+\lambda) y+1-\lambda=0 \end{aligned} \] Given line has equal intercepts…
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