TS EAMCET · Maths · Straight Lines
If the equation of the straight line passing through the point of intersection of \(x+2 y-19=0, x-2 y-3=0\) and which is at a perpendicular distance of 5 units from the point \((-2,4)\) is \(5 x+b y+c=0\), then a possible value of \(5+b+c\) is
- A -108
- B 10
- C 86
- D -14
Answer & Solution
Correct Answer
(D) -14
Step-by-step Solution
Detailed explanation
(d) Equation of line passing through the point of intersection of lines \(x+2 y-19=0\) and \(x-2 y-3=0\) is \((x+2 y-19)+\lambda(x-2 y-3)=0\) \(\Rightarrow(1+\lambda) x+(2-2 \lambda) y-(19+3 \lambda)=0\) is at a perpendicular distance of 5 units from point \((-2,4)\) So,…
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