TS EAMCET · Maths · Pair of Lines
The point of concurrence of all the chords of the curve \(3 x^2-y^2-2 x+4 y=0\) which subtend a right angle at the origin is
- A \((1,2)\)
- B \((1,-2)\)
- C \((-1,2)\)
- D \((-1,-2)\)
Answer & Solution
Correct Answer
(B) \((1,-2)\)
Step-by-step Solution
Detailed explanation
Let the equation of chord be \(l x+m y=1\) \(\begin{aligned} & \therefore \quad 3 x^2-y^2-2 x+4 y=0 \\ & 3 x^2-y^2-2 x(l x+m y)+4 y(l x+m y)=0 \\ & \Rightarrow 3 x^2-y^2-2 l x^2-2 m x y+4 l x y+4 m y^2=0 \\ & \Rightarrow(3-2 l) x^2+(4 m-1) y^2+(4 l-2 m) x y=0\end{aligned}\)…
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