ExamBro
ExamBro
TS EAMCET · Maths · Inverse Trigonometric Functions

If \(\tan ^{-1} \frac{1}{5}+\frac{1}{2} \sec ^{-1} x+\tan ^{-1} \frac{1}{8}=\frac{\pi}{8}\), then \(x^2=\)

  1. A \(\frac{12}{7}\)
  2. B \(\frac{50}{49}\)
  3. C \(\frac{13}{12}\)
  4. D \(\frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{50}{49}\)

Step-by-step Solution

Detailed explanation

We have, \(\begin{array}{r} \tan ^{-1} \frac{1}{5}+\frac{1}{2} \sec ^{-1} x+\tan ^{-1} \frac{1}{8}=\frac{\pi}{8} \\ \Rightarrow \quad\left(\tan ^{-1} \frac{1}{5}+\tan ^{-1} \frac{1}{8}\right)+\frac{1}{2} \sec ^{-1} x=\frac{\pi}{8} \end{array}\)…