TS EAMCET · Maths · Circle
Let \(x-4=0\) be the radical axis of two circles which are intersecting orthogonally. If \(x^2+y^2=36\) is one of those circles, then the other circle is
- A \(x^2+y^2-16 x+36=0\)
- B \(x^2+y^2-18 x+36=0\)
- C \(x^2+y^2-18 x+24=0\)
- D \(x^2+y^2-6 x+8 y+36=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-18 x+36=0\)
Step-by-step Solution
Detailed explanation
We have, equation of one circle \[ \begin{aligned} & x^2+y^2=36 \\ & \Rightarrow \quad x^2+y^2-36=0 \\ & \end{aligned} \] and radical axis of two circle is \(x-4=0\) So, equation of other circle is…
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