TS EAMCET · Maths · Vector Algebra
The point if intersection of the lines \(l_1: \mathbf{r}(t)=(\mathbf{i}-6 \mathbf{j}+2 \mathbf{k})+t(\mathbf{i}+2 \mathbf{j}+\mathbf{k})\) \(l_2: \mathbf{R}(u)=(4 \mathbf{j}+\mathbf{k})+u(2 \mathbf{i}+\mathbf{j}+2 \mathbf{k})\) is
- A \((4,4,5)\)
- B \((6,4,7)\)
- C \((8,8,9)\)
- D \((10,12,11)\)
Answer & Solution
Correct Answer
(C) \((8,8,9)\)
Step-by-step Solution
Detailed explanation
Put \(\mathbf{r}=x \mathbf{i}+y \mathbf{j}+z \mathbf{k}\) \(\therefore x \mathbf{i}+y \mathbf{j}+z \mathbf{k}=(\mathbf{i}-6 \mathbf{j}+2 \mathbf{k})+t(\mathbf{i}+2 \mathbf{j}+\mathbf{k})\) \(\therefore\) Any point on line is \(P(1+t,-6+2 t, 2+t)\) is satisfied the second…
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