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TS EAMCET · Maths · Continuity and Differentiability

If the function \(f: R \rightarrow R\) defined by \[ f(x)=\left\{\begin{array}{cc} a\left(\frac{1-\cos 2 x}{x^2}\right), & \text { for } x < 0 \ \frac{b}{x} & \text { for } x=0 \ \frac{\sqrt{x}}{\sqrt{4+\sqrt{x}}-2}, & \text { for } x>0 \end{array}\right. \] Is continuous at \(x=0\), then \(a+b=\)

  1. A 2
  2. B 4
  3. C 6
  4. D 8
Verified Solution

Answer & Solution

Correct Answer

(C) 6

Step-by-step Solution

Detailed explanation

We have, \[ f(x)=\left\{\begin{array}{cc} \frac{a(1-\cos 2 x)}{x^2}, & x 0 \end{array}\right. \] \(f(x)\) is continuous at \(x=0\) \[ \therefore \quad \lim _{x \rightarrow 0^{-}} f(x)=f(0) \] \[ \lim _{x \rightarrow 0^{-}} \frac{a(1-\cos 2 x)}{x^2}=b \]…
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