TS EAMCET · Maths · Basic of Mathematics
\(\text { If } \frac{2 x^2-3 x+5}{(x-7)^3}=\frac{\mathrm{A}}{x-7}+\frac{\mathrm{B}}{(x-7)^2}+\frac{\mathrm{C}}{(x-7)^3}\) then \(2 \mathrm{~A}-3 \mathrm{~B}+\mathrm{C}=\)
- A 0
- B 27
- C 11
- D 15
Answer & Solution
Correct Answer
(C) 11
Step-by-step Solution
Detailed explanation
Given \(\frac{2 x^2-3 x+5}{(x-7)^3}=\frac{A}{(x-7)}+\frac{B}{(x-7)^2}+\frac{C}{(x-7)^3}\)…
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