TS EAMCET · Maths · Hyperbola
Let \(P\left(\frac{\pi}{4}\right), Q\left(\frac{5 \pi}{4}\right), R\left(\frac{3 \pi}{4}\right), T\left(\frac{7 \pi}{4}\right)\) be the points on the hyperbola \(x^2-4 y^2-4=0\) in the parametric form. Then the area of the quadrilateral \(P Q R T\) is (in square units)
- A \(4 \sqrt{2}\)
- B \(16 \sqrt{2}\)
- C \(32 \sqrt{2}\)
- D \(8 \sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(8 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Equation of hyperbola \(x^2-4 y^2-4=0\) \[ \frac{x^2}{4}-\frac{y^2}{1}=1 \] Then, \(a=2, b=1\) Parametric point on hyperbola \(=(a \sec \theta, b \tan \theta)\) Then,…
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