TS EAMCET · Maths · Determinants
The number of solutions of the system of equations \(2 x+y-z=7, \quad x-3 y+2 z=1\), \(x+4 y-3 z=5\) is
- A 0
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
Given that, \(2 x+y-z=7\) \(\ldots\) (i) \(x-3 y+2 z=1\) \(\ldots\) (ii) and \(x+4 y-z=5\) \(\ldots\) (iii) From Eqs. (i) and (ii), \(5 x-y=15\) \(\ldots\) (iv) From Eqs. (i) and (iii), \(5 x-y=16\) \(\ldots\) (v) Equation (iv) and (v) shows that they are parallel and solution…
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