TS EAMCET · Maths · Straight Lines
If \(\alpha\) is the angle made by the perpendicular drawn from origin to the line \(3 x-4 y+5=0\) with positive \(X\)-axis in positive direction and \(a x+b y=1\) is the equation of a line passing through the point \((1,-1)\) with \(\tan \alpha\) as its slope, then \(a+a b+b=\)
- A \(11\)
- B \(13\)
- C \(17\)
- D \(19\)
Answer & Solution
Correct Answer
(D) \(19\)
Step-by-step Solution
Detailed explanation
Slope of perpendicular to \(3 x-4 y+5=0\) is \(\frac{-4}{3}\) \(\therefore \quad \tan \alpha=\frac{-4}{3}\) Equation of line through \((1,-1) ; y+1=\frac{-4}{3}(x-1)\)…
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