TS EAMCET · Maths · Quadratic Equation
If one root of the equation \(4 x^2-2 x+k-4=0\) is the reciprocal of the other, then the value of \(k\) is
- A \(-8\)
- B \(8\)
- C \(-4\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(8\)
Step-by-step Solution
Detailed explanation
\(4 x^2-2 x+K-4=0\) Roots are \(\alpha\) and \(\frac{1}{\alpha}\) \(\therefore \quad \alpha \cdot \frac{1}{\alpha}=\frac{K-4}{4} \Rightarrow 1=\frac{K-4}{4} \Rightarrow K=8 .\)
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