TS EAMCET · Maths · Vector Algebra
If the line \(\mathbf{r}=\mathbf{a}+t \mathbf{b}\) is parallel to the plane \(\mathbf{r}=\mathbf{c}+l \mathbf{d}+m \mathbf{e}\), then
- A \([\mathrm{abc}]=0\)
- B \([\mathrm{bcd}]=0\)
- C \([\mathrm{cde}]=0\)
- D \([\mathrm{bde}]=0\)
Answer & Solution
Correct Answer
(D) \([\mathrm{bde}]=0\)
Step-by-step Solution
Detailed explanation
We have, Line \(\mathbf{r}=\mathbf{a}+\mathbf{l} \mathbf{b}\) is paralleI to the plane \(\mathbf{r}=\mathbf{c}+l \mathbf{d}+m \mathbf{e}\) \(\therefore\) Normal vector of plane are \((\mathrm{d} \times \mathbf{e})\). Since, line and plane are parallel.
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