TS EAMCET · Maths · Straight Lines
The lines \(x-y-2=0, x+y-4=0\) and \(x+3 y=6\) meet in the common point :
- A \((1,2)\)
- B \((2,2)\)
- C \((3,1)\)
- D \((1,1)\)
Answer & Solution
Correct Answer
(C) \((3,1)\)
Step-by-step Solution
Detailed explanation
The equation of lines are \(x-y-2=0\) ...(i) \(x+y-4=0\) ...(ii) and \(\quad x+3 y=6\) ...(iii) On solving Eqs. (i) and (ii), we get \(x=3, y=1\) On putting these value in Eq. (iii) \(3+3=6\) which is satisfied. Thus the required point is \((3,1)\).
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