TS EAMCET · Maths · Quadratic Equation
The number of real roots of \(|x|^2-5|x|+6=0\) is
- A 2
- B 3
- C 4
- D 1
Answer & Solution
Correct Answer
(C) 4
Step-by-step Solution
Detailed explanation
We have, \[ |x|^2-5|x|+6=0 \] Let \[ |x|=y \] \[ \begin{aligned} & \Rightarrow & y^2-5 y+6 & =0 \\ \Rightarrow & & (y-2)(y-3) & =0 \\ \Rightarrow & & y & =2,3 \\ \Rightarrow & & |x| & =2 \text { or }|x|=3 \\ \Rightarrow & & x & = \pm 2 \text { or } \pm 3 \end{aligned} \]…
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