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TS EAMCET · Maths · Sequences and Series

\(\mathrm{t}_1, \mathrm{t}_2, \mathrm{t}_3, \ldots, \mathrm{t}_{\mathrm{n}}\) are positive integers, \(\mathrm{S}_{\mathrm{n}}=\mathrm{t}_1+\mathrm{t}_2+\mathrm{t}_3+\ldots+\mathrm{t}_{\mathrm{n}}, \mathrm{S}_1=1^2, \mathrm{~S}_2=3^2, \mathrm{~S}_3=6^2\), \(\mathrm{S}_4=10^2, \mathrm{~S}_5=15^2\) and similarly other terms are there. Following this pattern, if \(\mathrm{S}_{10}=\mathrm{k}^2\) then \(\mathrm{k}=\)

  1. A \(55\)
  2. B \(45\)
  3. C \(36\)
  4. D \(21\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(55\)

Step-by-step Solution

Detailed explanation

\(\mathrm{S}_{\mathrm{n}} = \left(\frac{\mathrm{n}(\mathrm{n}+1)}{2}\right)^2\) \(\mathrm{k} = \frac{10(10+1)}{2}\) \(\mathrm{k} = \frac{10 \times 11}{2}\) \(\mathrm{k} = 55\)