TS EAMCET · Maths · Sequences and Series
\(\mathrm{t}_1, \mathrm{t}_2, \mathrm{t}_3, \ldots, \mathrm{t}_{\mathrm{n}}\) are positive integers, \(\mathrm{S}_{\mathrm{n}}=\mathrm{t}_1+\mathrm{t}_2+\mathrm{t}_3+\ldots+\mathrm{t}_{\mathrm{n}}, \mathrm{S}_1=1^2, \mathrm{~S}_2=3^2, \mathrm{~S}_3=6^2\), \(\mathrm{S}_4=10^2, \mathrm{~S}_5=15^2\) and similarly other terms are there. Following this pattern, if \(\mathrm{S}_{10}=\mathrm{k}^2\) then \(\mathrm{k}=\)
- A \(55\)
- B \(45\)
- C \(36\)
- D \(21\)
Answer & Solution
Correct Answer
(A) \(55\)
Step-by-step Solution
Detailed explanation
\(\mathrm{S}_{\mathrm{n}} = \left(\frac{\mathrm{n}(\mathrm{n}+1)}{2}\right)^2\) \(\mathrm{k} = \frac{10(10+1)}{2}\) \(\mathrm{k} = \frac{10 \times 11}{2}\) \(\mathrm{k} = 55\)
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