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TS EAMCET · Maths · Differentiation

If \(\cos ^{-1}\left(\frac{y}{b}\right)=2 \log \left(\frac{x}{2}\right)\), where \(x>0\), then \(x^2 \frac{d^2 y}{d x^2}+x \frac{d y}{d x}\) is equal to

  1. A \(4 y\)
  2. B \(-4 y\)
  3. C \(0\)
  4. D \(-8 y\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-4 y\)

Step-by-step Solution

Detailed explanation

\[ \cos ^{-1}\left(\frac{y}{b}\right)=2 \log \left(\frac{x}{2}\right), x>0 \] On differentiating w.r.t. \(x\) we get…
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