TS EAMCET · Maths · Differentiation
If \(\cos ^{-1}\left(\frac{y}{b}\right)=2 \log \left(\frac{x}{2}\right)\), where \(x>0\), then \(x^2 \frac{d^2 y}{d x^2}+x \frac{d y}{d x}\) is equal to
- A \(4 y\)
- B \(-4 y\)
- C \(0\)
- D \(-8 y\)
Answer & Solution
Correct Answer
(B) \(-4 y\)
Step-by-step Solution
Detailed explanation
\[ \cos ^{-1}\left(\frac{y}{b}\right)=2 \log \left(\frac{x}{2}\right), x>0 \] On differentiating w.r.t. \(x\) we get…
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