TS EAMCET · Maths · Circle
The equation of the circle concentric with the circle \(x^2+y^2-6 x+12 y+15=0\) and of double its area is
- A \(x^2+y^2-6 x+12 y-15=0\)
- B \(x^2+y^2-6 x+12 y-30=0\)
- C \(x^2+y^2-6 x+12 y-25=0\)
- D \(x^2+y^2-6 x+12 y-20=0\)
Answer & Solution
Correct Answer
(A) \(x^2+y^2-6 x+12 y-15=0\)
Step-by-step Solution
Detailed explanation
The equation of the circle is \(S \equiv x^2+y^2-6 x+12 y+15=0\) Let the equation of concentric circle of given circles, is \(S_2=x^2+y^2-6 x+12 y+15=0\) On comparing the circle \(S_1\) with, \(x^2+y^2+2 g x+2 f y+c=0\) \(\Rightarrow \quad g=-3, f=6, c=15\) Then, radius of…
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