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TS EAMCET · Maths · Quadratic Equation

The maximum possible number of real roots of the equation \(x^{\frac{5}{5}}-6 x^2-4 x+5=0\) is

  1. A \(0\)
  2. B \(3\)
  3. C \(4\)
  4. D \(5\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3\)

Step-by-step Solution

Detailed explanation

Let \(f(x)=x^2-6 x^2-4 x+5\) \[ \Rightarrow f(-x)=-x^5-6 x^2+4 x+5 \] Number of changes of sign in \(f(x)\) are 2 and number of changes of sign in \(f(-x)\) are 1 . \(\therefore\) By descarte's rule of signs Maximum number of +ve real roots are 2 and \(-\mathrm{ve}\) real roots…