TS EAMCET · Maths · Differential Equations
The solution of the differential equation \(\frac{d y}{d x}-2 y \tan 2 x=e^x \sec 2 x\) is
- A \(y \sin 2 x=e^x+C\)
- B \(y \cos 2 x=e^x+C\)
- C \(y=e^x \cos 2 x+C\)
- D \(y \cos 2 x+e^x=C\)
Answer & Solution
Correct Answer
(B) \(y \cos 2 x=e^x+C\)
Step-by-step Solution
Detailed explanation
Given, differential equation is \[ \frac{d y}{d x}-2 y \tan 2 x=e^x \sec 2 x \] Here, \(P=2 \tan 2 x, Q=e^x \sec 2 x\)…
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