TS EAMCET · Maths · Indefinite Integration
\(\int \frac{x^2}{\left(\sqrt{4-x^2}\right)^3} d x=\)
- A \(\frac{x^2}{\sqrt{4-x^2}}-\sin ^{-1}\left(\frac{x}{2}\right)+C\)
- B \(\frac{x}{\sqrt{4-x^2}}-\tan ^{-1}\left(\frac{x}{\sqrt{4-x^2}}\right)+C\)
- C \(\frac{x}{\sqrt{4-x^2}}+\sin ^{-1}\left(\frac{2}{\sqrt{4-x^2}}\right)+C\)
- D \(\sqrt{4-x^2}-\tan ^{-1}\left(\frac{x}{2}\right)+C\)
Answer & Solution
Correct Answer
(B) \(\frac{x}{\sqrt{4-x^2}}-\tan ^{-1}\left(\frac{x}{\sqrt{4-x^2}}\right)+C\)
Step-by-step Solution
Detailed explanation
Given that, \(\int \frac{x^2}{\left(\sqrt{4-x^2}\right)^3} d x\) ...(i) Substituting, \(x=2 \sin \theta\) and \(d x=2 \cos \theta d \theta\) Putting in Eq. (i), \(=\int \frac{(2 \sin \theta)^2}{\left.(\sqrt{4-(2 \sin \theta})^2\right)^3} 2 \cos \theta d \theta\)…
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