TS EAMCET · Maths · Differentiation
On differentiation if we get \(f(x, y) d y-g(x, y) d x=0\) from \(2 x^2-3 x y+y^2+x+2 y-8=0\) then \(\frac{g(2,2)}{f(1,1)}=\)
- A \(\frac{11}{7}\)
- B \(-3\)
- C \(\frac{-1}{3}\)
- D \(7\)
Answer & Solution
Correct Answer
(B) \(-3\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}=\frac{g(x, y)}{f(x, y)}\) \(\begin{aligned} & 2 x^2-3 x y+y^2+x+2 y-8=0 \\ & 2(2 x)-3\left(x \cdot \frac{d y}{d x}+y\right)+2 y \frac{d y}{d x}+1+2 \frac{d y}{d x}=0\end{aligned}\)…
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