TS EAMCET · Maths · Complex Number
The locus of the point \(z=x+i y\) satisfying \(\left|\frac{z-2 i}{z+2 i}\right|=1\) is
- A \(x\)-axis
- B \(y\)-axis
- C \(y=2\)
- D \(x=2\)
Answer & Solution
Correct Answer
(A) \(x\)-axis
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Given, }\left|\frac{z-2 i}{z+2 i}\right|=1 \\ & \Rightarrow \quad \frac{|x+i y-2 i|}{|x+i y+2 i|}=1\end{aligned}\)…
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