TS EAMCET · Maths · Three Dimensional Geometry
\(L_1\) is a line passing through the points with position vectors \(\hat{\mathbf{i}}-2 \hat{\mathbf{j}}-\hat{\mathbf{k}}\) and \(4 \hat{\mathbf{i}}-3 \hat{\mathbf{k}}\). \(L_2\) is a line passing through the points with position vectors \(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}\) and \(2 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}-5 \hat{\mathbf{k}}\). Then the distance between \(L_1\) and \(L_2\) is
- A 0
- B \(\frac{3}{4}\)
- C \(\frac{4}{3}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{4}{3}\)
Step-by-step Solution
Detailed explanation
Equation of line \(L_1\) is \(\mathbf{r}=(\hat{\mathbf{i}}-2 \hat{\mathbf{j}}-\hat{\mathbf{k}})+\lambda(3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-2 \hat{\mathbf{k}})\) Equation of line \(L_2\) is…
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